Test - Revision history

Sbw at 13:32, 13 May 2010

2010-05-13T13:32:13Z

2010-05-10T20:13:04Z

2010-05-10T20:11:09Z

2010-05-10T20:09:00Z

2010-05-10T20:04:51Z

2010-05-10T18:39:04Z

2010-05-06T23:43:03Z

Created page with 'This is a test page.'

New page

This is a test page.

@@ Line 1: / Line 1: @@
-This is a test page.
+This is a ''test'' page.
-<math>
+<math>\operatorname{erfc}(x) =
    \frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =
-   \frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}
+   \frac{e^{-x^3}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}</math>

@@ Line 3: / Line 3: @@
 <math>
    \operatorname{erfc}(x) =
-   \frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^4}\,dt =
+   \frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =
    \frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}
 </math>

@@ Line 3: / Line 3: @@
 <math>
    \operatorname{erfc}(x) =
-   \frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^3}\,dt =
+   \frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^4}\,dt =
    \frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}
 </math>

@@ Line 3: / Line 3: @@
 <math>
    \operatorname{erfc}(x) =
-   \frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =
+   \frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^3}\,dt =
    \frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}
 </math>

@@ Line 1: / Line 1: @@
 This is a test page.
 <math>
    \operatorname{erfc}(x) =

← Older revision		Revision as of 18:39, 10 May 2010
Line 1:		Line 1:
	This is a test page.		This is a test page.
		+	<math>
		+	\operatorname{erfc}(x) =
		+	\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =
		+	\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}
		+	</math>